Voltage Drop & Wire Size Calculator

Enter the run, the load and the voltage, and get the voltage drop, the voltage at the load, and the smallest conductor from NEC Chapter 9 Table 8 that holds your target — with the ampacity check that voltage drop alone does not make.

Nominal, at the source
Sets the 2× / 1.732× factor
Table 8 values differ by about 65%
110.14(C) limits the ampacity column
Source to load — not the round trip
Nameplate or calculated load
3% branch · 5% feeder + branch (NEC notes)
Optional. Enforces 240.4(D) and the conductor ampacity floor.
Load current20 A
Recommended minimum size8 AWG Cu
Voltage drop at that size3.06 V · 2.55%
Voltage at the load116.94 V
Ampacity @ 60°C (8 AWG)40 A
Resistance @ 75°C0.764 Ω / 1,000 ft
Power lost in the conductors61 W
Governing constraintvoltage drop

Size ladder — drop at each size, 20 A over 100 ft:

SizeDrop%Amp
8 AWG3.06 V2.55%40 A
6 AWG1.96 V1.64%55 A
4 AWG1.23 V1.03%70 A
3 AWG0.98 V0.82%85 A
2 AWG0.78 V0.65%95 A
1 AWG0.62 V0.51%110 A

Drop math: Vd = 2 × L × I × R ÷ 1,000, with L the one-way length and R the Table 8 resistance in Ω per 1,000 ft at 75°C. Ampacity is NEC Table 310.16 for three or fewer current-carrying conductors at 30°C ambient, limited by 240.4(D) for 14, 12 and 10 AWG. No ambient-temperature or bundle derating (310.15) is applied — correct for derating yourself or confirm with a licensed electrician.

What voltage drop is, and why long runs get expensive

Voltage drop is the voltage lost pushing current through the resistance of the conductors themselves. The source delivers 240 V, the load at the far end sees 235.3 V, and the missing 4.7 V is real power dissipated as heat in the wire. On a short branch circuit it is a rounding error. On a 150 ft run to a shop, a pump or a subpanel, it is the difference between a tool that starts and one that trips its own overload.

The intuition is Ohm's law applied to the whole loop: voltage lost equals current times resistance, and the resistance of a conductor grows with its length and shrinks with its cross-sectional area. Doubling the run doubles the drop; doubling the area halves it. That is why the fix for a long run is almost always a bigger conductor, not a bigger breaker.

The formula, and where the 2 and the 1.732 come from

Single phase: Vd = 2 × L × I × R ÷ 1,000. The 2 is there because current travels out on one conductor and back on the other, so the loop is twice the one-way length. Enter the one-way run — the number you measured — and the formula accounts for the return trip. This is the single most common error in hand calculations: dropping the 2 and under-reporting the drop by half.

Three phase: Vd = 1.732 × L × I × R ÷ 1,000. The factor is √3, which falls out of the vector relationship between phase voltages. For a balanced three-phase load the neutral carries no current, so the return path does not pay the same penalty as it does in a single-phase circuit.

Divide the result by the system voltage and multiply by 100 for a percentage. L is one-way length in feet, I is the load in amps, and R is the conductor resistance in ohms per 1,000 ft at 75°C from NEC Chapter 9 Table 8. Note what the formula does not include: power factor, reactance, or the temperature of the conductor in service. Table 8 is a dc-resistance table; Chapter 9 Table 9 lists ac effective impedance for anyone doing a rigorous ac calculation. For residential and light-commercial runs under a few hundred feet, Table 8 is what most electricians use, and this calculator follows that convention — stated openly rather than hidden.

NEC Chapter 9 Table 8 — resistance chart

These are the numbers the calculator walks to find your minimum size. Resistance is per 1,000 ft at 75°C for uncoated conductors, so a 100 ft one-way run uses R ÷ 10, and the loop resistance for single phase is twice that.

NEC Chapter 9 Table 8 — dc resistance at 75°C, uncoated conductors (Ω per 1,000 ft)
SizeCopperAluminium
14 AWG3.075.06
12 AWG1.933.18
10 AWG1.212.00
8 AWG0.7641.26
6 AWG0.4910.808
4 AWG0.3080.508
3 AWG0.2450.403
2 AWG0.1940.319
1 AWG0.1540.253
1/0 AWG0.1220.201
2/0 AWG0.09670.159
3/0 AWG0.07660.126
4/0 AWG0.06080.100
250 kcmil0.05150.0847
300 kcmil0.04290.0707
350 kcmil0.03670.0605
400 kcmil0.03210.0529
500 kcmil0.02580.0424

Two things to read off that chart. First, resistance is almost proportional to 1 ÷ area: going up three sizes (12 to 8 AWG) cuts resistance from 1.93 to 0.764, a factor of 2.5, which is what makes a long run affordable on a small circuit. Second, aluminium sits at about 1.6× the resistance of the same size in copper, so a 6 AWG aluminium conductor performs roughly like a 4 AWG copper one for voltage drop — and roughly 1.5 sizes worse for ampacity.

Ampacity — the check voltage drop does not make

A conductor can be electrically fine for voltage drop and still be illegal, because voltage drop says nothing about whether the wire can carry the current without overheating. That is ampacity, and it comes from NEC Table 310.16. The base table assumes no more than three current-carrying conductors in a raceway, cable or direct burial, at 30°C ambient. Ampacity, not voltage drop, is what decides whether a conductor is legal.

NEC Table 310.16 — allowable ampacity, ≤3 current-carrying conductors, 30°C ambient
SizeCu 60°CCu 75°CAl 60°CAl 75°C
14 AWG1520——
12 AWG20251520
10 AWG30352530
8 AWG40503540
6 AWG55654050
4 AWG70855565
3 AWG851006575
2 AWG951157590
1 AWG11013085100
1/0 AWG125150100120
2/0 AWG145175115135
3/0 AWG165200130155
4/0 AWG195230150180
250 kcmil215255170205
300 kcmil240285195230
350 kcmil260310210250
400 kcmil280335225270
500 kcmil320380260310

Two rules ride on top of that table. First, 240.4(D) caps the overcurrent device for the small conductors outright: 15 A on 14 AWG copper, 20 A on 12 AWG copper, 30 A on 10 AWG copper, and 15 A and 25 A on 12 and 10 AWG aluminium. Those limits do not bend because the 75°C column looks better. Second, 110.14(C) limits you to the ampacity column the terminations are rated for — for circuits of 100 A or less, that is normally the 60°C column unless every device in the circuit is listed for 75°C. That single sentence is why so many real-world runs land one size larger than a back-of-the-envelope calculation suggests. The calculator has a terminations selector for exactly this reason, and it defaults to 60°C. The same table with the full size range and the 90°C column, plus the ambient and conductor-bundle derating factors, is on the NEC 310.16 wire ampacity chart.

What this calculator does not do: ambient-temperature correction and conductor-bundle adjustment (NEC 310.15(B) and (C)) are not applied, parallel conductors are not modelled, and no load calculation is done for you. Enter the load the circuit is rated for, apply your own derating, and have anything unusual checked by a licensed electrician.

Worked example — 32 A over 150 ft at 240 V

A 7.7 kW load drawing 32 A on a 240 V single-phase circuit, 150 ft from the panel. Start with 6 AWG copper, R = 0.491 Ω per 1,000 ft.

Vd = 2 × 150 × 32 × 0.491 ÷ 1,000 = 4.714 V. Check it by hand in two steps if you want: 2 × 150 = 300 ft of conductor; 300 ÷ 1,000 = 0.3; 0.3 × 0.491 = 0.1473 Ω of loop resistance; 0.1473 × 32 A = 4.714 V. As a percentage, 4.714 ÷ 240 × 100 = 1.96%, comfortably inside the 3% target, and the load still sees 235.3 V.

Ampacity holds too: 6 AWG copper is 55 A at 60°C, so a 40 A breaker is fine. The power burned in that run is 32 A × 4.714 V = 151 W while the load runs — 0.3% or so of the load, but over a working day it is a small heater inside your wall. If the run were 300 ft instead, the drop would double to 9.4 V (3.9%) and 6 AWG would fail the target; the calculator would walk you to 4 AWG, which drops 5.8 V, or 2.4%.

Worked example — why a 100 ft, 20 A circuit at 120 V needs 8 AWG

12 AWG is the default answer for a 20 A circuit, and at 30 ft it is the right one. At 100 ft it is not. Vd = 2 × 100 × 20 × 1.93 ÷ 1,000 =7.72 V, which at 120 V is 6.4% — more than twice the design target, with the load seeing 112.3 V. Step up to 10 AWG: 2 × 100 × 20 × 1.21 ÷ 1,000 = 4.84 V, still 4.0%. Step up to 8 AWG: 3.06 V, or 2.6%, and 8 AWG copper carries 40 A at 60°C so a 20 A breaker is well inside it. That is the answer, and it is the kind of result that surprises people who size by breaker alone.

Now move the same circuit to 240 V and nothing else changes: the drop is still 7.72 V on 12 AWG, but 7.72 ÷ 240 = 3.2% instead of 6.4%. Drop in volts depends on current and resistance; drop in percent depends on the voltage you started with. That is why 240 V tools and 240 V subpanels tolerate distance so much better than 120 V circuits.

Common mistakes

Sizing a feeder out to a subpanel is the same two checks applied to a bigger load — ampacity first, then distance. The worked version, with a 100 A / 240 V distance table and the 83% rule that people wrongly apply to subpanels, is in the what size wire for a 100 amp subpanel guide, and the 200 A case is in the what size wire for a 200 amp service guide.

Voltage drop FAQ

How do I calculate voltage drop?

Single phase: Vd = 2 × L × I × R ÷ 1,000, where L is the one-way run in feet, I is the load in amps and R is the conductor resistance in ohms per 1,000 ft from NEC Chapter 9 Table 8. Three phase: use 1.732 × L × I × R ÷ 1,000. Divide the result by the system voltage and multiply by 100 for a percentage. Example: 32 A over 150 ft of 6 AWG copper at 240 V gives 2 × 150 × 32 × 0.491 ÷ 1,000 = 4.71 V, or 1.96%.

Is 3% voltage drop a code requirement?

Not in the base NEC. The 3% branch-circuit and 5% total figures live in informational notes to NEC 210.19(A)(1) and 215.2(A)(1) — not enforceable rules, per 90.5(C). Many jurisdictions, utilities and specs do enforce them anyway, and they are a sound design target. Treat 3% at the farthest outlet as the goal, and check your local amendments or job spec.

What wire size do I need for a 100 ft run?

Length is what makes long runs need bigger wire, and the answer depends on the load and the voltage. A 20 A load at 120 V over 100 ft of 12 AWG copper drops 2 × 100 × 20 × 1.93 ÷ 1,000 = 7.72 V, which is 6.4% — too much. 8 AWG copper drops 3.06 V, or 2.6%, and carries 40 A at 60°C, so 8 AWG is the answer there. At 240 V the same 20 A over 100 ft only drops 1.3% on 12 AWG, because drop is a percentage of a higher voltage.

Does voltage drop change the wire size I need for a breaker?

They are two separate checks. Ampacity (NEC Table 310.16) and the small-conductor limits in 240.4(D) decide the smallest conductor a breaker may protect — 15 A on 14 AWG, 20 A on 12 AWG, 30 A on 10 AWG copper. Voltage drop decides how much bigger the conductor has to be to keep the load voltage up. You size for the larger of the two, which is why a 20 A circuit 100 ft out often ends up on 8 AWG.

Related calculators and guides

Long runs usually end at something structural. If the circuit feeds a detached shop, the concrete slab guide and the concrete calculator cover the pad, the rebar and footing calculator sizes the reinforcement, and the deck footing calculator handles the posts. For trench drainage alongside the conduit, use the drain pipe slope calculator. If you are working on the building rather than the service, the header size calculator and the stair math guide cover the framing side.

This calculator sizes the conductor for distance. The device that protects it is a separate answer: the breaker size chart covers the standard ratings in NEC Table 240.6(A), the 125% rule for continuous loads, and the breaker and wire for water heaters, dryers, ranges, air conditioners and mini-splits. The conductor's own ampacity, with the ambient and bundle corrections, is on the Table 310.16 ampacity chart.